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Home > CC2 > Chapter 5 > Lesson 5.3.2

Lesson 5.1.1, lesson 5.1.2, lesson 5.2.1, lesson 5.2.2, lesson 5.2.3, lesson 5.2.4, lesson 5.2.5, lesson 5.2.6, lesson 5.3.1, lesson 5.3.2, lesson 5.3.3, lesson 5.3.4, lesson 5.3.5.

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5th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.

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enVision MATH Common Core 5, Grade: 5 Publisher: Scott Foresman Addison Wesley

Envision math common core 5, title : envision math common core 5, publisher : scott foresman addison wesley, isbn : 328672637, isbn-13 : 9780328672639, use the table below to find videos, mobile apps, worksheets and lessons that supplement envision math common core 5., textbook resources.

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Math Homework Pages and Answers

Topic 1: understand place value.

1-1: Patterns with Exponents and Powers of 10

• Homework Page

1-2: Understand Whole-Number Place Value

1-3: Decimals to Thousandths

1-4: Understand Decimal Place Value

1-5: Compare Decimals

1-6: Round Decimals

Topic 2: Use Models and Strategies to Add and Subtract Decimals

2-2: Estimate Sums and Differences of Decimals

2-3: Use Models to Add and Subtract Decimals

2-4: Use Strategies to Add Decimals

2-5: Use Strategies to Subtract Decimals

2-6: Model with Math

Topic 3: Fluently Multiply Multi-Digit Whole Numbers

3-1: Multiply Greater Numbers by Powers of 10

3-2: Estimate Products

3-3: Multiply by 1-Digit Numbers

3-4: Multiply 2-Digit by 2-Digit Numbers

3-5: Multiply 3-Digit by 2-Digit Numbers

3-6: Multiply Whole Numbers with Zeros

3-7: Practice Multiplying Multi-Digit Numbers

3-8: Solve Word Problems

3-9: Critique Reasoning

Topic 4: Use Models and Strategies to Multiply Decimals

4-1:Multiply Decimals by Powers of 10

4-2: Estimate the Product of a Decimal and a Whole Number 

4-3: Use Models to Multiply a Decimal and a Whole Number

4-4: Multiply a Decimal and a Whole Number

4-5: Use Models to Multiply a Decimal and a Decimal

4-6: Multiply Decimals Using Partial Products

4-7: Use Properties to Multiply Decimals

4-8: Use Number Sense to Multiply Decimals

4-9: Model with Math

Topic 5: Use Models and Strategies to Divide Whole Numbers

Topic 5-1: Use Patterns and Mental Math to Divide

Topic 5-2: Estimate Quotients with 2-Digit Divisors

Topic 5-3: Use Models and Properties to Divide with 2-Digit Divisors

Topic 5-4: Use Partial Quotients to Divide

Topic 5-5: Use Sharing to Divide: Two Digit Divisors

Topic 5-6: Use Sharing to Divide: Greater Dividends

Topic 5-7: Choose a Strategy to Divide 

Lesson 5-8: Make Sense and Persevere

Topic 6: Use Models and Strategies to Divide Decimals

6-1: Patterns for Dividing with Decimals

6-2: Estimate Decimals Quotients

6-3: Use Models to Divide by a 1-Digit Number

6-4: Divide by a 2-digit Whole Number

6-5: Divide by a Decimal

6-6: Reasoning 

Topic 7: Use Equivalent Fractions to Add and Subtract Fractions

7-2: Find Common Denominators

•   Answers

7-3: Add Fractions with Unlike Denominators

7-4: Subtract Fractions with Unlike Denominators

7-5: Add and Subtract Fractions

7-6: Estimate Sums and Differences of Mixed Numbers

7-7: Use Models to Add Mixed Numbers

7-8: Add Mixed Numbers

7-9: Use Models to Subtract Mixed Numbers

7-10: Subtract Mixed Numbers

7-11: Add and Subtract Mixed Numbers

Topic 8: Apply Understanding of Multiplication to Multiply Fractions

8-1: Multiply a Fraction by a Whole Number

8-2: Multiply a Whole Number by a Fraction

8-3: Multiply Fractions and Whole Numbers

8-4: Use Models to Multiply Two Fractions

8-5: Multiply Two Fractions

8-6: Area of a Rectangle

8-7: Multiply Mixed Numbers

Topic 9: Apply Understanding of Division to Divide Fractions

Lesson 9-1: Fractions and Division

Lesson 9-2: Fractions and Mixed Numbers as Quotients

Lesson 9-3: Use Multiplication to Divide

Lesson 9-4: Divide Whole Numbers by Unit Fractions

Lesson 9-5: Divide Unit Fractions by Non-Zero Whole Numbers

Lesson 9-6: Divide Whole Numbers and Unit Fractions

Lesson 9-7: Solve Problems Using Division

Lesson 9-8: Repeated Reasoning

Topic 10: Represent and Interpret Data

Lesson 10-1: Analyze Line Plots

Lesson 10-2: Make Line Plots

Lesson 10-3: Solve Word Problems Using Measurement Data

Lesson 10-4: Critique Reasoning 

Topic 11: Understand Volume Concepts

Lesson 11-1: Model Volume

Lesson 11-2: Develop a Formula

Lesson 11-3: Combine Volume of Prisms

Lesson 11-4: Solve Word Problems Using Volume

Lesson 11-5: Use Appropriate Tools

5th Grade Homework Policy

We value your family time. therefore, we will be intentional with any homework we send home. students’ daily homework will be required reading of at least 30 minutes., students will have nightly math homework which supports our learning in class. there are a lot of new math concepts in 5th grade and it is important for students' growth and understanding. additionally, study guides and other assignments may be sent home periodically throughout the year., please note: if a student exhibits off-task behaviors, fails to complete an assignment, or is struggling to understand a concept, an assignment will be sent home for completion..

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Polygons - Lesson 11.1

Triangles - Lesson 11.2

Quadrilaterals - Lesson 11.3

Three Dimensional Figures - Lesson 11.5

Unit Cubes and Solid Figures - Lesson 11.6

Understanding Volume - Lesson 11.7

Estimate Volume - Lesson 11.8

Volume of a Rectangular Prism - Lesson 11.9

Apply Volume Formulas - Lesson 11.10

Finding Volume of Composite Formulas - Lesson 11.12

Find a Part of a Group - Lesson 7.1

Multiply Fractions and Whole Numbers - Lesson 7.2

Fraction and Whole Number Multiplication - Lesson 7.3

Multiply Fractions - Lesson 7.4

Compare Fraction Factor and Product - Lesson 7.5

Fraction Multiplication - Lesson 7.6

Area and Mixed Numbers - Lesson 7.7

Compare Mixed Number Factors and Products - Lesson 7.8

Multiply Mixed Numbers - Lesson 7.9

Problem Solving - Find Unknown Lengths - Lesson 7.10  

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Line Plots - Lesson 9.1

Ordered Pairs - Lesson 9.2

Graph Data - Lesson 9.3

Line Graphs - Lesson 9.4

Numerical Patterns - Lesson 9.5

Problem Solving - Find a Rule - Lesson 9.6

Graph and Analyze Relationships - Lesson 9.7

Customary Length - Lesson 10.1

Customary Capacity - Lesson 10.2

Weight - Lesson 10.3

Multistep Measurement Problems - Lesson 10.4

Metric Measures - Lesson 10.5

Problem Solving Conversions - Lesson 10.6

Elapsed Time - Lesson 10.7

Division Patterns with Decimals - Lesson 5.1

Divide Decimals by Whole Numbers - Lesson 5.2

Estimate Quotients - lesson 5.3

Division of Decimals by Whole Numbers - Lesson 5.4

Decimal Division - Lesson 5.5

Divide Decimals - Lesson 5.6

Write Zeros in the Dividend - Lesson 5.7

Problem Solving - Decimal Operations - Lesson 5.8

Divide Fractions and Whole Numbers - Lesson 8.1

Problem Solving - Use Multiplication - Lesson 8.2

Connect Fractions to Division - Lesson 8.3

Fraction and Whole Number Division - Lesson 8.4

Interpret Division with Fractions - Lesson 8.5

Addition with Unlike Denominators - Lesson 6.1

Subtraction with Unlike Denominators - Lesson 6.2

Estimate Fraction Sums and Differences - Lesson 6.3

Common Denominators and Equivalent Fractions - Lesson 6.4

Add or Subtract Fractions - Lesson 6.5

Add or Subtract Mixed Numbers - Lesson 6.6

Subtraction with Renaming - Lesson 6.7

Patterns with Fractions - Lesson 6.8

Problem Solving with Addition and Subtraction - Lesson 6.9

Use Properties of Addition - Lesson 6.10

Multiplication Patterns with Decimals - Lesson 4.1

Multiply Decimals and Whole Numbers - Lesson 4.2

Multiply Decimals and Whole Numbers - Lesson 4.3

Multiply Using Expanded Form - Lesson 4.4

Problem Solving - Multiply Money - Lesson 4.5

Decimal Multiplication - Lesson 4.6

Multiply Decimals - Lesson 4.7

Thousandths - Lesson 3.1

Place Value of Decimals - Lesson 3.2

Compare and Order Decimals - Lesson 3.3

Round Decimals - Lesson 3.4

Decimal Addition - Lesson 3.5

Decimal Subtraction - Lesson 3.6

Estimate Decimal Sums and Differences - Lesson 3.7

Add Decimals - Lesson 3.8

Subtract Decimals - Lesson 3.9

Patterns with Decimals - Lesson 3.10

Problem Solving Add and Subtract Money - Lesson 3.11

Choose a Method - Lesson 3.12

Performance Task on Chapter 3

Place the First Digit - Lesson 2.1

Divide by 1-Digit Divisors - Lesson 2.2

Division with 2-Digit Divisors - Lesson 2.3

Partial Quotients - Lesson 2.4

Estimate with 2-Digit Divisors - Lesson 2.5

Divide by 2-Digit Divisors - Lesson 2.6

Interpret the Remainder - Lesson 2.7

Adjust Quotients - Lesson 2.8

Problem Solving - Division - Lesson 2.9

Performance Task on Chapter 2

Fifth Grade 

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Texas Go Math Grade 5 Lesson 5.3 Answer Key Estimate Fraction Sums and Differences

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 5.3 Answer Key Estimate Fraction Sums and Differences.

Unlock the Problem

Kimberly will be riding her bike to school this year. The distance from her house to the end of the Street is \(\frac{1}{62}\)mile. The distance from the end of the Street to the school is \(\frac{3}{8}\) mile. About how far is Kimberly’s house from school?

You can use benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

STEP 3: Add the rounded fractions.

Another Way

Use mental math. You can compare the numerator and the denominator to round a fraction and find a reasonable estimate.

Estimate. \(\frac{9}{10}\) – \(\frac{5}{8}\) STEP 1: Round \(\frac{9}{10}\). Think: The numerator is about the same as the denominator. Round the fraction \(\frac{9}{10}\) to __________.

Remember A fraction with the same numerator and denominator, such as \(\frac{2}{2}, \frac{5}{5}, \frac{12}{12}\) or \(\frac{96}{96}\), is equal to 1.

STEP 2: Round \(\frac{5}{8}\) Think: The numerator is about half the denominator. Round the fraction \(\frac{5}{8}\) to ___________.

STEP 1: Round \(\frac{9}{10}\). Think: The numerator is about the same as the denominator. Round the fraction \(\frac{9}{10}\) to \(\frac{10}{10}\)

STEP 2: Round \(\frac{5}{8}\) Think: The numerator is about half the denominator. Round the fraction \(\frac{5}{8}\) to \(\frac{4}{8}\)

Math Talk Mathematical Processes

Explain another way you could use benchmarks to estimate \(\frac{9}{10}\) – \(\frac{5}{8}\). Answer: \(\frac{9}{10}\) – \(\frac{5}{8}\) = \(\frac{1}{6}\) \(\frac{1}{6}\) is very near to \(\frac{1}{5}\) Explanation: Used bench marks to find the sum

Share and Show

Estimate the sum or difference.

Question 1. \(\frac{5}{6}\) + \(\frac{3}{8}\) a. Round \(\frac{5}{6}\) to its closest benchmark. Answer:  \(\frac{6}{6}\)

b. Round \(\frac{3}{8}\) to its closest benchmark. Answer: \(\frac{4}{8}\)

c. Add to find the estimate.   \(\frac{6}{6}\) +\(\frac{4}{8}\)  = 1\(\frac{1}{2}\) Answer: 1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Go Math Lesson 5.3 5th Grade Answer Key Question 2. \(\frac{5}{9}\) – \(\frac{3}{8}\) Answer: a. Round \(\frac{5}{9}\) to its closest benchmark. Answer:  \(\frac{5}{9}\)

c. Add to find the estimate.   \(\frac{5}{9}\) – \(\frac{4}{8}\)  = 1\(\frac{1}{18}\) Answer: 1\(\frac{1}{18}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 3. \(\frac{5}{6}\) + \(\frac{2}{5}\) Answer: a. Round \(\frac{5}{6}\) to its closest benchmark. Answer:  \(\frac{6}{6}\)

b. Round \(\frac{2}{5}\) to its closest benchmark. Answer: \(\frac{2}{5}\)

c. Add to find the estimate.   \(\frac{6}{6}\) +\(\frac{2}{5}\)  = 1\(\frac{1}{2}\) Answer: 1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 4. \(\frac{9}{10}\) – \(\frac{1}{9}\) Answer: a. Round \(\frac{9}{10}\) to its closest benchmark. Answer:  \(\frac{10}{10}\)

b. Round \(\frac{1}{9}\) to its closest benchmark. Answer: \(\frac{0}{9}\)

c. Add to find the estimate.   \(\frac{10}{10}\) – \(\frac{0}{9}\)  = 1 Answer: 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Problem Solving

Lesson 5.3 Answer Key 5th Grade Go Math Question 5. How do you know whether your estimate for \(\frac{9}{10}\) + 3\(\frac{6}{7}\) would be greater than or less than the actual sum? Explain. Answer: Greater than the actual sum \(\frac{9}{10}\) + 3\(\frac{6}{7}\) = close to bench marks \(\frac{10}{10}\) + 3\(\frac{7}{7}\) =  4 Explanation: Is greater than the actual sum used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 6. Write Math Nick estimated that \(\frac{5}{8}\) + \(\frac{4}{7}\) is about 2. Explain how you know his estimate is not reasonable. Answer: \(\frac{5}{8}\) + \(\frac{4}{7}\) close to benchmarks \(\frac{4}{8}\) + \(\frac{4}{7}\) = 1 Explanation: Nick estimated that \(\frac{5}{8}\) + \(\frac{4}{7}\) is about 2. used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1. so, his estimation is wrong

Question 7. Lisa and Valerie are picnicking in Trough Creek State Park in Pennsylvania. Lisa has brought a salad that she made with \(\frac{3}{4}\) cup of strawberries, \(\frac{7}{8}\) cup of peaches, and \(\frac{1}{6}\) cup of blueberries. About how many total cups of fruit are in the salad? Answer: \(\frac{3}{4}\) + \(\frac{7}{8}\) + \(\frac{1}{6}\) very close to bench marks \(\frac{4}{4}\) + \(\frac{8}{8}\) + \(\frac{0}{6}\) =2 \(\frac{1}{2}\) Explanation: Lisa and Valerie are picnicking in Trough Creek State Park in Pennsylvania. Lisa has brought a salad that she made with \(\frac{3}{4}\) cup of strawberries, \(\frac{7}{8}\) cup of peaches, and \(\frac{1}{6}\) cup of blueberries. 2\(\frac{1}{2}\)   total cups of fruit are in the salad

Go Math 5th Grade Lesson 5.3 How to Estimate Fractions Question 9. H.O.T Explain how you know that \(\frac{5}{8}\) + \(\frac{6}{10}\) is greater than 1. Answer: No Explanation: Close to the bench marks \(\frac{8}{8}\) + \(\frac{5}{10}\) = 1 actual sum is greater than 1

Daily Assessment Task

Fill in the bubble completely to show your answer.

Question 10. Mia uses \(\frac{1}{5}\) of a bag of gravel in the morning and \(\frac{11}{12}\) of a bag in the afternoon. About how much gravel does she use in one day? (A) 0 bags (B) \(\frac{1}{2}\) bag (C) 1 bag (D) 2\(\frac{1}{2}\) bags Answer:  C \(\frac{1}{5}\) + \(\frac{11}{12}\) nearest benchmarks are \(\frac{0}{5}\) + \(\frac{12}{12}\)  = 1 Explanation: Mia uses \(\frac{1}{5}\) of a bag of gravel in the morning and \(\frac{11}{12}\) of a bag in the afternoon. she use 1 bag of gravel

Question 11. Evaluate Reasonableness Hector and Veronica are going hiking. They made a trail mix that has \(\frac{2}{3}\) cup of almonds, \(\frac{7}{8}\) cup of peanuts, and \(\frac{4}{5}\) cup of raisins in it. Hector estimates that they made about 3 cups of trail mix. Is the estimate greater than or less than the actual sum? How do you know? (A) The estimate is greater because each fraction is rounded up to a benchmark. (B) The estimate is less because each fraction is rounded down to a benchmark. (C) The estimate is greater because they really made more than 3 cups. (D) The estimate is less because each fraction is rounded up to a benchmark. Answer: A Explanation: \(\frac{2}{3}\) + \(\frac{7}{8}\) + \(\frac{4}{5}\) rounded to the nearest benchmarks \(\frac{3}{3}\) + \(\frac{8}{8}\) + \(\frac{5}{5}\) = 3 Evaluated Reasonableness Hector and Veronica are going hiking. They made a trail mix that has \(\frac{2}{3}\) cup of almonds, ” \(\frac{7}{8}\) cup of peanuts, and \(\frac{4}{5}\) cup of raisins in it. Hector estimates that they made about 3 cups of trail mix.

Lesson 5.3 Go Math 5th Grade Answer Key Question 12. Multi-Step Amanda picked \(\frac{3}{5}\) pound of blueberries at her local farm yesterday. She used \(\frac{3}{8}\) pound of blueberries. Today she picked \(\frac{4}{5}\) pound of blueberries. About how many pounds of blueberries does Amanda have now? (A) \(\frac{1}{5}\)lb (B) 1 lb (C) \(\frac{1}{2}\)lb (D) 1\(\frac{1}{2}\)lbs Answer: B Explanation: what she bought is that she used yesterday in today marked to nearest benchmarks \(\frac{4}{5}\)  is \(\frac{5}{5}\) that is 1

Texas Test Prep

Question 13. Jake added \(\frac{1}{8}\) cup of sunflower seeds and \(\frac{4}{5}\) cup of banana chips to his sundae. Which is the best estimate of the total amount of toppings Jake added to his sundae? (A) about 2 cups (B) about 1 cup (C) about 1\(\frac{1}{2}\) cups (D) about \(\frac{1}{2}\) cup Answer: B Explanation: Jake added \(\frac{1}{8}\) cup of sunflower seeds and \(\frac{4}{5}\) cup of banana chips to his sundae. The best estimate of the total amount of toppings Jake added to his sundae is 1 cup

Texas Go Math Grade 5 Lesson 5.3 Homework and Practice Answer Key

Question 1. \(\frac{3}{8}\) + \(\frac{4}{5}\) = ___________ Answer: \(\frac{3}{8}\) + \(\frac{4}{5}\) rounded to the nearest benchmarks \(\frac{4}{8}\) + \(\frac{5}{5}\) = 1 \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

5th Grade Go Math Lesson 5.3 Answer Key Question 2. \(\frac{9}{10}\) – \(\frac{3}{8}\) = ___________ Answer: \(\frac{9}{10}\) – \(\frac{3}{8}\) rounded to the nearest benchmarks \(\frac{10}{10}\) – \(\frac{4}{8}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 3. \(\frac{5}{8}\) + \(\frac{2}{5}\) = ___________ Answer: \(\frac{5}{8}\) + \(\frac{2}{5}\) rounded to the nearest benchmarks \(\frac{4}{8}\) + \(\frac{2}{5}\) = 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 4. \(\frac{6}{7}\) + \(\frac{3}{5}\) = ___________ Answer: \(\frac{6}{7}\) + \(\frac{3}{5}\) rounded to the nearest benchmarks \(\frac{7}{7}\) + \(\frac{2}{5}\) = 1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 5. \(\frac{3}{8}\) – \(\frac{1}{6}\) = ___________ Answer: \(\frac{3}{8}\) – \(\frac{1}{6}\) rounded to the nearest benchmarks \(\frac{4}{8}\) – \(\frac{0}{6}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 6. \(\frac{7}{12}\) + \(\frac{1}{7}\) = ___________ Answer: \(\frac{7}{12}\) + \(\frac{1}{7}\) rounded to the nearest benchmarks \(\frac{6}{12}\) + \(\frac{0}{7}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Go Math Lesson 5.3 5th Grade Homework Answer Key Question 7. \(\frac{4}{9}\) – \(\frac{5}{8}\) = ___________ Answer: \(\frac{4}{9}\) – \(\frac{5}{8}\) rounded to the nearest benchmarks \(\frac{5}{9}\) – \(\frac{4}{8}\) = 0 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 8. \(\frac{1}{9}\) + \(\frac{5}{6}\) = ___________ Answer: \(\frac{1}{9}\) + \(\frac{5}{6}\) rounded to the nearest benchmark \(\frac{0}{9}\) + \(\frac{6}{6}\) = 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 9. \(\frac{7}{8}\) + \(\frac{4}{7}\) = ___________ Answer: \(\frac{7}{8}\) + \(\frac{4}{7}\) rounded to the nearest bench mark \(\frac{8}{8}\) + \(\frac{4}{7}\) =1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 10. \(\frac{1}{5}\) + \(\frac{3}{8}\) = ___________ Answer: \(\frac{1}{5}\) + \(\frac{3}{8}\) rounded to the nearest benchmark \(\frac{0}{5}\) + \(\frac{4}{8}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 11. \(\frac{7}{9}\) – \(\frac{2}{6}\) = ___________ Answer: \(\frac{7}{9}\) – \(\frac{2}{6}\) rounded to the nearest benchmark \(\frac{9}{9}\) – \(\frac{3}{6}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Go Math Grade 5 Lesson 5.3 Homework Answer Key Question 12. \(\frac{9}{10}\) – \(\frac{7}{8}\) = ___________ Answer: \(\frac{9}{10}\) – \(\frac{7}{8}\) rounded to the benchmarks \(\frac{10}{10}\) – \(\frac{8}{8}\) = 0 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 13. Explain how you can estimate the sum of \(\frac{4}{5}\) and \(\frac{1}{6}\). Answer: \(\frac{4}{5}\) + \(\frac{1}{6}\) rounded to the nearest bench marks \(\frac{5}{5}\) + \(\frac{0}{6}\) = 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 14. Jena uses \(\frac{7}{8}\) cup of raisins for muffins and \(\frac{5}{8}\) cup of raisins for a bowl of oatmeal. Does lena need more than or less than 1 cup of raisins to make muffins and oatmeal? Explain. Answer: more than 1 cup of raisins Explanation: Jena uses \(\frac{7}{8}\) cup of raisins for muffins and \(\frac{5}{8}\) cup of raisins for a bowl of oatmeal. \(\frac{7}{8}\) + \(\frac{5}{8}\) rounded the benhmark \(\frac{8}{8}\) + \(\frac{4}{8}\) = 1\(\frac{1}{2}\)

Question 15. A group of students ate \(\frac{5}{12}\) of a cheese pizza, \(\frac{7}{8}\) of a pepperoni pizza, and \(\frac{5}{8}\) of a veggie pizza. About how many pizzas were eaten? Answer: \(\frac{5}{12}\) + \(\frac{7}{8}\) + \(\frac{5}{8}\) rounded to the nearest benchmark \(\frac{6}{12}\) + \(\frac{8}{8}\) + \(\frac{4}{8}\) = 2 Explanation: A group of students ate \(\frac{5}{12}\) of a cheese pizza, \(\frac{7}{8}\) of a pepperoni pizza, and \(\frac{5}{8}\) of a veggie pizza. 2 pizzas were eaten in whole.

Lesson Check

Question 16. On Saturday, the scouts hiked \(\frac{4}{5}\) mile up the mountain. On Sunday, they hiked \(\frac{1}{4}\) mile up the mountain. About how far did the scouts hike up the mountain in all? (A) \(\frac{1}{2}\) mile (B) 1 mile (C) 1\(\frac{1}{2}\) miles (D) 2 miles Answer: \(\frac{4}{5}\) + \(\frac{1}{4}\) rounded to nearest benchmark \(\frac{5}{5}\) + \(\frac{0}{4}\)  is 1 mile Explanation: On Saturday, the scouts hiked \(\frac{4}{5}\) mile up the mountain. On Sunday, they hiked \(\frac{1}{4}\) mile up the mountain. 1 mile far the scouts hike up the mountain in all

Question 17. Which of the following best describes the difference for \(\frac{11}{12}\) – \(\frac{7}{10}\) ? (A) less than \(\frac{1}{2}\) (B) greater than \(\frac{1}{2}\) (C) greater than 1 (D) greater than 1\(\frac{1}{2}\) Answer: A Explanation: \(\frac{11}{12}\) – \(\frac{7}{10}\) is 0 that is less than \(\frac{1}{2}\)

Practice and Homework Lesson 5.3 Answer Key 5th Grade Question 18. Which sum is greatest? Use estimation to decide. (A) \(\frac{2}{7}\) + \(\frac{3}{8}\) (B) \(\frac{1}{10}\) + \(\frac{3}{8}\) (C) \(\frac{1}{6}\) + \(\frac{1}{8}\) (D) \(\frac{2}{9}\) + \(\frac{1}{8}\) Answer: A Explanation: \(\frac{2}{7}\) + \(\frac{3}{8}\) = 1

Question 20. Multi-Step Michaela has \(\frac{11}{12}\) yard of orange fabric and \(\frac{7}{8}\) yard of green fabric. She uses \(\frac{1}{2}\) yard of each color for her sewing project. About how much fabric does Michaela have left if she combines the two colors? (A) 1 yard (B) \(\frac{1}{2}\) yard (C) 1 \(\frac{1}{2}\) yards (D) 2 yards Answer:  D \(\frac{11}{12}\) + \(\frac{7}{8}\) rounded to nearest bench marks \(\frac{12}{12}\) + \(\frac{8}{8}\) = 2 Explanation: 2 yards fabric uses Michaela have left if she combines the two colors.

Question 21. Multi-Step Dustin buys \(\frac{9}{10}\) yard of striped fabric. He uses \(\frac{3}{8}\) yard. He buys \(\frac{7}{8}\) yard more. About how much fabric does Dustin have now? (A) 1 yard (B) \(\frac{1}{2}\) yard (C) 1\(\frac{1}{2}\) yards (D) 2 yards Answer: C Explanation: Dustin buys \(\frac{9}{10}\) yard of striped fabric. He uses \(\frac{3}{8}\) yard. He buys \(\frac{7}{8}\) yard more. \(\frac{9}{10}\) + \(\frac{3}{8}\)  + \(\frac{7}{8}\)  rounded to nearest benchmarks \(\frac{10}{10}\) – \(\frac{4}{8}\)  + \(\frac{8}{8}\)  = 1\(\frac{1}{2}\) yards

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Chapter 5: Ratios and Proportions

Chapter 5 homework solutions.

5.1-5.3 Extra Practice Worksheet

5.1 Ratios and Rates

5.1 Lesson Preso

5.1 Textbook Exercises: page 167

Ba: 1-6, 11-27 odd;

Avg: 1-6, 11-21 odd, 24-28 even, 29, 31;

Adv: 1-6, 18-38 even

5.2 Proportions

5.2 Textbook Exercises page 174

Ba: 1-4, 5-13 odd, 21-27 odd;

Avg 1-4, 5-13 odd, 22-30 even;

Adv: 1-4, 6-14 even, 22-32 even

5.3 Writing Proportions

5.3 Lesson Preso

5.3 Textbook Exercises page 182

Ba: 1-3, 9, 11, 12, 13-23 odd

Avg: 1-3, 8-14 even, 19-23

Adv: 1-3, 8-24 even, 25

5.4 Solving Proportions

5.4 Lesson Preso

5.4 Textbook Exercises page 190

Ba: 1-3, 5-9 odd, 15-21 odd, 22, 23-27 odd

Avg: 1-3, 5-9 odd, 15-21 odd, 22, 29, 30, 32-35

Adv: 1-3, 4-8 even, 14-38 even

5.5 Lesson Preso

5.5 Textbook Exercises page 196

Ba: 1-3, 5-11 odd, 12, 13-17 odd

Avg: 1-3, 5-11 odd, 12, 14-17

Adv: 1-3, 4-18 even

5.6 Direct Variation

5.6 Lesson Preso

5.6 Textbook Exercises page 202

Ba: 1-3, 7-17 odd, 18, 19-25 odd

Avg: 1-3, 7-17 odd, 18-28 even

Adv: 1-3, 8-28 even

Chapter 5 Review

5.1-5.3 Review Quizizz:

5.4-5.6 Review Quizizz:

Chapter 5 Review Quizizz:

• Texas Go Math
• Big Ideas Math
• Engageny Math
• McGraw Hill My Math
• enVision Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
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Eureka Math Grade 5 Module 3 Lesson 7 Answer Key

Engage ny eureka math 5th grade module 3 lesson 7 answer key, eureka math grade 5 module 3 lesson 7 sprint answer key.

Question 1. \(\frac{2}{4}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{2}{4}\) = \(\frac{1}{2}\) Explanation : \(\frac{2}{4}\) when its numerator and denominator is divided by 2 we get \(\frac{1}{2}\)

Question 2. \(\frac{2}{6}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{2}{6}\) = \(\frac{1}{3}\) Explanation : \(\frac{2}{6}\) when its numerator and denominator is divided by 2 we get \(\frac{1}{3}\)

Question 3. \(\frac{2}{8}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{2}{8}\) = \(\frac{1}{4}\) Explanation : \(\frac{2}{8}\) when its numerator and denominator is divided by 2 we get \(\frac{1}{4}\)

Question 4. \(\frac{5}{10}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{5}{10}\) = \(\frac{1}{2}\) Explanation : \(\frac{5}{10}\) when its numerator and denominator is divided by 5 we get \(\frac{1}{2}[/latex

Question 5. [latex]\frac{5}{15}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{5}{15}\) = \(\frac{1}{3}\) Explanation : \(\frac{5}{15}\) when its numerator and denominator is divided by 5 we get \(\frac{1}{3}\)

Question 6. \(\frac{5}{20}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{5}{20}\) = \(\frac{1}{4}\) Explanation : \(\frac{5}{20}\) when its numerator and denominator is divided by 5 we get \(\frac{1}{4}\)

Question 7. \(\frac{4}{8}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{4}{8}\) = \(\frac{1}{2}\) Explanation : \(\frac{4}{8}\) when its numerator and denominator is divided by 4 we get \(\frac{1}{2}\)

Question 8. \(\frac{4}{12}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{4}{12}\) = \(\frac{1}{3}\) Explanation : \(\frac{4}{12}\) when its numerator and denominator is divided by 4 we get \(\frac{1}{3}\)

Question 9. \(\frac{4}{16}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{4}{16}\) = \(\frac{1}{4}\) Explanation : \(\frac{4}{16}\) when its numerator and denominator is divided by 4 we get \(\frac{1}{4}\)

Question 10. \(\frac{3}{6}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{3}{6}\) = \(\frac{1}{2}\) Explanation : \(\frac{3}{6}\) when its numerator and denominator is divided by 3 we get \(\frac{1}{2}\)

Question 11. \(\frac{3}{9}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{3}{9}\) = \(\frac{1}{3}\) Explanation : \(\frac{3}{9}\) when its numerator and denominator is divided by 3 we get \(\frac{1}{3}\)

Question 12. \(\frac{3}{12}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{3}{12}\) = \(\frac{1}{4}\) Explanation : \(\frac{3}{12}\) when its numerator and denominator is divided by 3 we get \(\frac{1}{4}\)

Question 13. \(\frac{4}{6}\) = \(\frac{2}{3}\) \(\frac{1}{3}\) Answer: \(\frac{4}{6}\) = \(\frac{2}{3}\) Explanation : \(\frac{4}{6}\) when its numerator and denominator is divided by 2 we get \(\frac{2}{3}\)

Question 14. \(\frac{6}{12}\) = \(\frac{2}{3}\) \(\frac{1}{2}\) Answer: \(\frac{6}{12}\) = \(\frac{1}{2}\) Explanation : \(\frac{6}{12}\) when its numerator and denominator is divided by 6 we get \(\frac{1}{2}\)

Question 15. \(\frac{6}{18}\) = \(\frac{2}{3}\) \(\frac{1}{3}\) Answer: \(\frac{6}{18}\) = \(\frac{1}{3}\) Explanation : \(\frac{6}{18}\) when its numerator and denominator is divided by 6 we get \(\frac{1}{3}\)

Question 16. \(\frac{6}{30}\) = \(\frac{1}{5}\) \(\frac{1}{3}\) Answer: \(\frac{6}{30}\) = \(\frac{1}{5}\) Explanation : \(\frac{6}{30}\) when its numerator and denominator is divided by 6 we get \(\frac{1}{5}\)

Question 17. \(\frac{6}{9}\) = \(\frac{2}{3}\) \(\frac{1}{3}\) Answer: \(\frac{6}{9}\) = \(\frac{2}{3}\) Explanation : \(\frac{6}{9}\) when its numerator and denominator is divided by 3 we get \(\frac{2}{3}\)

Question 18. \(\frac{7}{14}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{7}{14}\) = \(\frac{1}{2}\) Explanation : \(\frac{7}{14}\) when its numerator and denominator is divided by 7 we get \(\frac{1}{2}\)

Question 19. \(\frac{7}{21}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{7}{21}\) = \(\frac{1}{3}\) Explanation : \(\frac{7}{21}\) when its numerator and denominator is divided by 7 we get \(\frac{1}{3}\)

Question 20. \(\frac{7}{42}\) = \(\frac{1}{6}\) \(\frac{1}{7}\) Answer: \(\frac{7}{42}\) = \(\frac{1}{6}\) Explanation : \(\frac{7}{42}\) when its numerator and denominator is divided by 7 we get \(\frac{1}{6}\)

Question 21. \(\frac{8}{12}\) = \(\frac{2}{3}\) \(\frac{3}{4}\) Answer: \(\frac{8}{12}\) = \(\frac{2}{3}\) Explanation : \(\frac{8}{12}\) when its numerator and denominator is divided by 4 we get \(\frac{2}{3}\)

Question 22. \(\frac{9}{18}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{9}{18}\) = \(\frac{1}{2}\) Explanation : \(\frac{9}{18}\) when its numerator and denominator is divided by 9 we get \(\frac{1}{2}\)

Question 23. \(\frac{9}{27}\) = \(\frac{2}{3}\) \(\frac{1}{3}\) \(\frac{1}{4}\) Answer: \(\frac{9}{27}\) = \(\frac{1}{3}\) Explanation : \(\frac{9}{27}\) when its numerator and denominator is divided by 9 we get \(\frac{1}{3}\)

Question 24. \(\frac{9}{63}\) = \(\frac{1}{6}\) \(\frac{1}{7}\) \(\frac{1}{8}\) Answer: \(\frac{9}{63}\) = \(\frac{1}{7}\) Explanation : \(\frac{9}{63}\) when its numerator and denominator is divided by 9 we get \(\frac{1}{7}\)

Question 25. \(\frac{8}{12}\) = \(\frac{2}{3}\) \(\frac{3}{4}\) \(\frac{4}{5}\) Answer: \(\frac{8}{12}\) = \(\frac{2}{3}\) Explanation : \(\frac{8}{12}\) when its numerator and denominator is divided by 4 we get \(\frac{2}{3}\)

Question 26. \(\frac{8}{16}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) \(\frac{1}{4}\) Answer: \(\frac{8}{16}\) = \(\frac{1}{2}\) Explanation : \(\frac{8}{16}\) when its numerator and denominator is divided by 8 we get \(\frac{1}{2}\)

Question 27. \(\frac{8}{24}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) \(\frac{1}{4}\) Answer: \(\frac{8}{24}\) = \(\frac{1}{3}\) Explanation : \(\frac{8}{24}\) when its numerator and denominator is divided by 8 we get \(\frac{1}{3}\)

Question 28. \(\frac{8}{64}\) = \(\frac{1}{7}\) \(\frac{1}{8}\) \(\frac{1}{9}\) Answer: \(\frac{8}{64}\) = \(\frac{1}{8}\) Explanation : \(\frac{8}{64}\) when its numerator and denominator is divided by 8 we get \(\frac{1}{8}\)

Question 29. \(\frac{12}{18}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{12}{18}\) = \(\frac{2}{3}\) Explanation : \(\frac{12}{18}\) when its numerator and denominator is divided by 6 we get \(\frac{2}{3}\)

Question 30. \(\frac{12}{16}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{12}{16}\) = \(\frac{3}{4}\) Explanation : \(\frac{12}{16}\) when its numerator and denominator is divided by 4 we get \(\frac{3}{4}\)

Question 31. \(\frac{9}{12}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{9}{12}\) = \(\frac{3}{4}\) Explanation : \(\frac{9}{12}\) when its numerator and denominator is divided by 3 we get \(\frac{3}{4}\)

Question 32. \(\frac{6}{8}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{6}{8}\) = \(\frac{3}{4}\) Explanation : \(\frac{6}{8}\) when its numerator and denominator is divided by 2 we get \(\frac{3}{4}\)

Question 33. \(\frac{10}{12}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{10}{12}\) = \(\frac{5}{6}\) Explanation : \(\frac{10}{12}\) when its numerator and denominator is divided by 2 we get \(\frac{5}{6}\)

Question 34. \(\frac{15}{18}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{15}{18}\) = \(\frac{5}{6}\) Explanation : \(\frac{15}{18}\) when its numerator and denominator is divided by 3 we get \(\frac{5}{6}\)

Question 35. \(\frac{8}{10}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{8}{10}\) = \(\frac{4}{5}\) Explanation : \(\frac{8}{10}\) when its numerator and denominator is divided by 2 we get \(\frac{4}{5}\)

Question 36. \(\frac{16}{20}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{16}{20}\) = \(\frac{4}{5}\) Explanation : \(\frac{16}{20}\) when its numerator and denominator is divided by 4 we get \(\frac{4}{5}\)

Question 37. \(\frac{12}{15}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{12}{15}\) = \(\frac{4}{5}\) Explanation : \(\frac{12}{15}\) when its numerator and denominator is divided by 3 we get \(\frac{4}{5}\)

Question 38. \(\frac{18}{27}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{18}{27}\) = \(\frac{2}{3}\) Explanation : \(\frac{18}{27}\) when its numerator and denominator is divided by 9 we get \(\frac{2}{3}\)

Question 39. \(\frac{27}{36}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{27}{36}\) = \(\frac{3}{4}\) Explanation : \(\frac{27}{36}\) when its numerator and denominator is divided by 9 we get \(\frac{3}{4}\)

Question 40. \(\frac{32}{40}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{32}{40}\) = \(\frac{4}{5}\) Explanation : \(\frac{32}{40}\) when its numerator and denominator is divided by 8 we get \(\frac{4}{5}\)

Question 41. \(\frac{45}{54}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{5}{6}\) Answer: \(\frac{45}{54}\) = \(\frac{5}{6}\) Explanation : \(\frac{45}{54}\) when its numerator and denominator is divided by 9 we get \(\frac{5}{6}\)

Question 42. \(\frac{24}{36}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{24}{36}\) = \(\frac{2}{3}\) Explanation : \(\frac{24}{36}\) when its numerator and denominator is divided by 12 we get \(\frac{2}{3}\)

Question 43. \(\frac{60}{72}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{60}{72}\) = \(\frac{5}{6}\) Explanation : \(\frac{60}{72}\) when its numerator and denominator is divided by 12 we get \(\frac{5}{6}\)

Question 44. \(\frac{48}{60}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{5}{6}\) Answer: \(\frac{48}{60}\) = \(\frac{4}{5}\) Explanation : \(\frac{48}{60}\) when its numerator and denominator is divided by 12 we get \(\frac{4}{5}\)

Question 1. \(\frac{5}{10}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{5}{10}\) = \(\frac{1}{2}\) Explanation : \(\frac{5}{10}\) when its numerator and denominator is divided by 5 we get \(\frac{1}{2}\)

Question 2. \(\frac{5}{15}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{5}{15}\) = \(\frac{1}{3}\) Explanation : \(\frac{5}{15}\) when its numerator and denominator is divided by 5 we get \(\frac{1}{3}\)

Question 3. \(\frac{5}{20}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{5}{20}\) = \(\frac{1}{4}\) Explanation : \(\frac{5}{20}\) when its numerator and denominator is divided by 5 we get \(\frac{1}{4}\)

Question 4. \(\frac{2}{4}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{2}{4}\) = \(\frac{1}{2}\) Explanation : \(\frac{2}{4}\) when its numerator and denominator is divided by 2 we get \(\frac{1}{2}\)

Question 5. \(\frac{2}{6}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{2}{6}\) = \(\frac{1}{3}\) Explanation : \(\frac{2}{6}\) when its numerator and denominator is divided by 2 we get \(\frac{1}{3}\)

Question 6. \(\frac{2}{8}\) = \(\frac{1}{2}\) \(\frac{1}{4}\) Answer: \(\frac{2}{8}\) = \(\frac{1}{4}\) Explanation : \(\frac{2}{8}\) when its numerator and denominator is divided by 2 we get \(\frac{1}{4}\)

Question 7. \(\frac{3}{6}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{3}{6}\) = \(\frac{1}{2}\) Explanation : \(\frac{3}{6}\) when its numerator and denominator is divided by 3 we get \(\frac{1}{2}\)

Question 8. \(\frac{3}{9}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{3}{9}\) = \(\frac{1}{3}\) Explanation : \(\frac{3}{9}\) when its numerator and denominator is divided by 3 we get \(\frac{1}{3}\)

Question 9. \(\frac{3}{12}\) = \(\frac{1}{4}\) \(\frac{1}{3}\) Answer: \(\frac{3}{12}\) = \(\frac{1}{4}\) Explanation : \(\frac{3}{12}\) when its numerator and denominator is divided by 3 we get \(\frac{1}{4}\)

Question 10. \(\frac{4}{8}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{4}{8}\) = \(\frac{1}{2}\) Explanation : \(\frac{4}{8}\) when its numerator and denominator is divided by 4 we get \(\frac{1}{2}\)

Question 11. \(\frac{4}{12}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{4}{12}\) = \(\frac{1}{3}\) Explanation : \(\frac{4}{12}\) when its numerator and denominator is divided by 4 we get \(\frac{1}{3}\)

Question 12. \(\frac{4}{16}\) = \(\frac{1}{4}\) \(\frac{1}{3}\) Answer: \(\frac{4}{16}\) = \(\frac{1}{4}\) Explanation : \(\frac{4}{16}\) when its numerator and denominator is divided by 4 we get \(\frac{1}{4}\)

Question 13. \(\frac{4}{6}\) = \(\frac{2}{3}\) \(\frac{1}{2}\) Answer: \(\frac{4}{6}\) = \(\frac{2}{3}\) Explanation : \(\frac{4}{6}\) when its numerator and denominator is divided by 2 we get \(\frac{2}{3}\)

Question 14. \(\frac{7}{14}\) = \(\frac{2}{3}\) \(\frac{1}{2}\) Answer: \(\frac{7}{14}\) = \(\frac{1}{2}\) Explanation : \(\frac{7}{14}\) when its numerator and denominator is divided by 7 we get \(\frac{1}{2}\)

Question 15. \(\frac{7}{21}\) = \(\frac{1}{5}\) \(\frac{1}{3}\) Answer: \(\frac{7}{21}\) = \(\frac{1}{3}\) Explanation : \(\frac{7}{21}\) when its numerator and denominator is divided by 7 we get \(\frac{1}{3}\)

Question 16. \(\frac{7}{35}\) = \(\frac{1}{5}\) \(\frac{1}{3}\) Answer: \(\frac{7}{35}\) = \(\frac{1}{5}\) Explanation : \(\frac{7}{35}\) when its numerator and denominator is divided by 7 we get \(\frac{1}{5}\)

Question 18. \(\frac{6}{12}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{6}{12}\) = \(\frac{1}{2}\) Explanation : \(\frac{6}{12}\) when its numerator and denominator is divided by 6 we get \(\frac{1}{2}\)

Question 19. \(\frac{6}{18}\) = \(\frac{1}{6}\) \(\frac{1}{3}\) Answer: \(\frac{6}{18}\) = \(\frac{1}{3}\) Explanation : \(\frac{6}{18}\) when its numerator and denominator is divided by 6 we get \(\frac{1}{3}\)

Question 20. \(\frac{6}{36}\) = \(\frac{1}{6}\) \(\frac{1}{3}\) Answer: \(\frac{6}{36}\) = \(\frac{1}{6}\) Explanation : \(\frac{6}{36}\) when its numerator and denominator is divided by 6 we get \(\frac{1}{6}\)

Question 22. \(\frac{8}{16}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) Answer: \(\frac{8}{16}\) = \(\frac{1}{2}\) Explanation : \(\frac{8}{16}\) when its numerator and denominator is divided by 8 we get \(\frac{1}{2}\)

Question 23. \(\frac{8}{24}\) = \(\frac{2}{3}\) \(\frac{1}{3}\) \(\frac{1}{4}\) Answer: \(\frac{8}{24}\) = \(\frac{1}{3}\) Explanation : \(\frac{8}{24}\) when its numerator and denominator is divided by 8 we get \(\frac{1}{3}\)

Question 24. \(\frac{8}{56}\) = \(\frac{1}{6}\) \(\frac{1}{7}\) \(\frac{1}{8}\) Answer: \(\frac{8}{24}\) = \(\frac{1}{3}\) Explanation : \(\frac{8}{56}\) when its numerator and denominator is divided by 8 we get \(\frac{1}{7}\)

Question 26. \(\frac{9}{18}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) \(\frac{1}{4}\) Answer: \(\frac{9}{18}\) = \(\frac{1}{2}\) Explanation : \(\frac{9}{18}\) when its numerator and denominator is divided by 9 we get \(\frac{1}{2}\)

Question 27. \(\frac{9}{27}\) = \(\frac{1}{2}\) \(\frac{1}{3}\) \(\frac{1}{4}\) Answer: \(\frac{9}{27}\) = \(\frac{1}{3}\) Explanation : \(\frac{9}{27}\) when its numerator and denominator is divided by 9 we get \(\frac{1}{3}\)

Question 28. \(\frac{9}{72}\) = \(\frac{1}{7}\) \(\frac{1}{8}\) \(\frac{1}{9}\) Answer: \(\frac{9}{72}\) = \(\frac{1}{8}\) Explanation : \(\frac{9}{72}\) when its numerator and denominator is divided by 9 we get \(\frac{1}{8}\)

Question 30. \(\frac{6}{8}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{6}{8}\) = \(\frac{3}{4}\) Explanation : \(\frac{6}{8}\) when its numerator and denominator is divided by 2 we get \(\frac{3}{4}\)

Question 32. \(\frac{12}{16}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{12}{16}\) = \(\frac{3}{4}\) Explanation : \(\frac{12}{16}\) when its numerator and denominator is divided by 4 we get \(\frac{3}{4}\)

Question 33. \(\frac{8}{10}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{8}{10}\) = \(\frac{4}{5}\) Explanation : \(\frac{8}{10}\) when its numerator and denominator is divided by 2 we get \(\frac{4}{5}\)

Question 34. \(\frac{16}{20}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{16}{20}\) = \(\frac{4}{5}\) Explanation : \(\frac{16}{20}\) when its numerator and denominator is divided by 4 we get \(\frac{4}{5}\)

Question 35. \(\frac{12}{15}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{12}{15}\) = \(\frac{4}{5}\) Explanation : \(\frac{12}{15}\) when its numerator and denominator is divided by 3 we get \(\frac{4}{5}\)

Question 36. \(\frac{10}{12}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{5}{6}\) Answer: \(\frac{10}{12}\) = \(\frac{5}{6}\) Explanation : \(\frac{10}{12}\) when its numerator and denominator is divided by 2 we get \(\frac{5}{6}\)

Question 37. \(\frac{15}{18}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{15}{18}\) = \(\frac{5}{6}\) Explanation : \(\frac{15}{18}\) when its numerator and denominator is divided by 3 we get \(\frac{5}{6}\)

Question 38. \(\frac{16}{24}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{16}{24}\) = \(\frac{2}{3}\) Explanation : \(\frac{16}{24}\) when its numerator and denominator is divided by 8 we get \(\frac{2}{3}\)

Question 39. \(\frac{24}{32}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{24}{32}\) = \(\frac{3}{4}\) Explanation : \(\frac{24}{32}\) when its numerator and denominator is divided by 12 we get \(\frac{3}{4}\)

Question 40. \(\frac{36}{45}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{2}{3}\) Answer: \(\frac{36}{45}\) = \(\frac{4}{5}\) Explanation : \(\frac{36}{45}\) when its numerator and denominator is divided by 9 we get \(\frac{4}{5}\)

Question 41. \(\frac{40}{48}\) = \(\frac{3}{4}\) \(\frac{4}{5}\) \(\frac{5}{6}\) Answer: \(\frac{40}{48}\) = \(\frac{5}{6}\) Explanation : \(\frac{40}{48}\) when its numerator and denominator is divided by 8 we get \(\frac{5}{}\)

Question 43. \(\frac{48}{60}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{4}{5}\) Answer: \(\frac{48}{60}\) = \(\frac{4}{5}\) Explanation : \(\frac{48}{60}\) when its numerator and denominator is divided by 12 we get \(\frac{4}{5}\)

Question 44. \(\frac{60}{72}\) = \(\frac{3}{4}\) \(\frac{5}{6}\) \(\frac{2}{3}\) Answer: \(\frac{60}{72}\) = \(\frac{5}{6}\) Explanation : \(\frac{60}{72}\) when its numerator and denominator is divided by 12 we get \(\frac{5}{6}\)

Eureka Math Grade 5 Module 3 Lesson 7 Problem Set Answer Key

Eureka Math Grade 5 Module 3 Lesson 7 Exit Ticket Answer Key

Eureka Math Grade 5 Module 3 Lesson 7 Homework Answer Key

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