case study probability class 8

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CBSE Class 8 Mathematics- Chapter 5- Data Handling- Chance and Probability Notes. The chance of happening of an event is known as probability.

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Case Study Questions for Class 8 Maths

• Last modified on: 8 months ago
• Reading Time: 7 Minutes

Table of Contents

Here in this article, we are providing case study questions for class 8 maths.

Maths Class 8 Chapter List

Latest chapter list (2023-24).

Chapter 1 Rational Numbers Chapter 2 Linear Equations in One Variable Chapter 3 Understanding Quadrilaterals Chapter 4 Data Handling Chapter 5 Squares and Square Roots Chapter 6 Cubes and Cube Roots Chapter 7 Comparing Quantities Chapter 8 Algebraic Expressions and Identities Chapter 9 Mensuration Chapter 10 Exponents and Powers Chapter 11 Direct and Indirect proportions Chapter 12 Factorisation Chapter 13 Introduction to Graphs

Old Chapter List

Chapter 1 Rational Numbers Chapter 2 Linear Equations in One Variable Chapter 3 Understanding Quadrilaterals Chapter 4 Practical Geometry Chapter 5 Data Handling Chapter 6 Squares and Square Roots Chapter 7 Cubes and Cube Roots Chapter 8 Comparing Quantities Chapter 9 Algebraic Expressions and Identities Chapter 10 Visualising Solid Shapes Chapter 11 Mensuration Chapter 12 Exponents and Powers Chapter 13 Direct and Indirect proportions Chapter 14 Factorisation Chapter 15 Introduction to Graphs Chapter 16 Playing with Numbers

Tips for Answering Case Study Questions for Class 8 Maths in Exam

1. Comprehensive Reading for Context: Prioritize a thorough understanding of the provided case study. Absorb the contextual details and data meticulously to establish a strong foundation for your solution.

2. Relevance Identification: Pinpoint pertinent mathematical concepts applicable to the case study. By doing so, you can streamline your thinking process and apply appropriate methods with precision.

3. Deconstruction of the Problem: Break down the complex problem into manageable components or steps. This approach enhances clarity and facilitates organized problem-solving.

4. Highlighting Key Data: Emphasize critical information and data supplied within the case study. This practice aids quick referencing during the problem-solving process.

5. Application of Formulas: Leverage pertinent mathematical formulas, theorems, and principles to solve the case study. Accuracy in formula selection and unit usage is paramount.

6. Transparent Workflow Display: Document your solution with transparency, showcasing intermediate calculations and steps taken. This not only helps track progress but also offers insight into your analytical process.

7. Variable Labeling and Definition: For introduced variables or unknowns, offer clear labels and definitions. This eliminates ambiguity and reinforces a structured solution approach.

8. Step Explanation: Accompany each step with an explanatory note. This reinforces your grasp of concepts and demonstrates effective application.

9. Realistic Application: When the case study pertains to real-world scenarios, infuse practical reasoning and logic into your solution. This ensures alignment with real-life implications.

10. Thorough Answer Review: Post-solving, meticulously review your answer for accuracy and coherence. Assess its compatibility with the case study’s context.

11. Solution Recap: Before submission, revisit your solution to guarantee comprehensive coverage of the problem and a well-organized response.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format.

13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration.

14. Maintain Composure and Confidence: Approach questions with poise and self-assurance. Your preparation equips you to conquer the challenges presented.

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Free Printable Probability Worksheets for 8th Class

Probability-focused Math worksheets for Class 8 students to discover and enhance their understanding of probability concepts. Download and print these free resources from Quizizz for a comprehensive learning experience.

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Probability worksheets for Class 8 are essential tools for teachers looking to enhance their students' understanding of math concepts, specifically in the areas of data analysis and graphing. These worksheets provide a variety of exercises and problems that challenge students to apply their knowledge of probability, helping them develop critical thinking and problem-solving skills. With a focus on real-world applications, these Class 8 math worksheets cover topics such as calculating the probability of simple and compound events, using tree diagrams and tables, and understanding conditional probability. By incorporating these worksheets into their lesson plans, teachers can ensure that their students are well-prepared for more advanced mathematical concepts in the future. Probability worksheets for Class 8 are a valuable resource for any math educator looking to strengthen their students' grasp of this important topic.

Quizizz is an excellent platform for teachers to access a wide variety of Probability worksheets for Class 8, as well as other math resources. This interactive platform offers engaging and customizable quizzes, worksheets, and games that can be easily integrated into lesson plans or used for homework assignments. With Quizizz, teachers can track their students' progress in real-time, allowing them to identify areas where students may need additional support or practice. In addition to Probability worksheets for Class 8, Quizizz also offers resources for other math topics, such as algebra, geometry, and data analysis, ensuring that teachers have access to a comprehensive suite of materials to support their instruction. By utilizing Quizizz in their classrooms, teachers can provide their students with a fun and effective way to learn and practice essential math skills.

RS Aggarwal Class 8 Solutions Exercise 25A Chapter 25 Probability

Get the Latest Edition of RS Aggarwal Solutions Class 8 Chapter 25 Probability Exercise 25A. Probability RS Aggarwal Class 8 Maths Solutions helps you to revise the complete syllabus and score excellent marks.

RS Aggarwal Solutions Class 8 Chapter 25 Ex 25A

Also, check the solutions of other exercises from below.

• Chapter 25 Probability Exercise 25B

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• CBSE- Data handling
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• STUDY MATERIAL FOR CBSE CLASS 8 MATH
• Chapter 1 - Algebraic Expressions and Identities
• Chapter 2 - Comparing Quantities
• Chapter 3 - Cubes and Cube Roots
• Chapter 4 - Data handling
• Chapter 5 - Direct and Inverse Proportions
• Chapter 6 - Exponents and Powers
• Chapter 7 - Factorization
• Chapter 8 - Introduction to Graphs
• Chapter 9 - Mensuration
• Chapter 10 - Playing with Numbers
• Chapter 11 - Practical Geometry
• Chapter 12 - Squares and Square Roots
• Chapter 13 - Visualizing Solid Shapes
• Chapter 14 - Linear Equations in One Variable
• Chapter 15 - Rational Numbers
• Chapter 16 - Understanding Quadrilaterals

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Case Based Questions (MCQ)

• Miscellaneous
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• Bernoulli Trial

Question 1 - Case Based Questions (MCQ) - Chapter 13 Class 12 Probability

Last updated at April 8, 2024 by Teachoo

A coach is training 3 players. He observes that the player A can hit a target 4 times in 5 shots, player B can hit 3 times in 4 shots and the player C can hit 2 times in 3 shots.

From this situation answer the following:.

Let the target is hit by A, B and C. Then, the probability that A, B and, C all will hit, is

(a) 4/5 , (b) 3/5 , (c) 2/5 .

Referring to (i), what is the probability that B, C will hit and A will lose?

(a) 1/10 , (b) 3/10 , (c) 7/10 .

With reference to the events mentioned in (i), what is the probability that ‘any two of A, B and C will hit?

(a) 1/30 , (b) 11/30 , (c) 17/30 .

What is the probability that ‘none of them will hit the target’?

(b) 1/60 , (c) 1/15 .

What is the probability that at least one of A, B or C will hit the target?

(a) 59/60 , (b) 2/5 , (c) 3/5 .

Question A coach is training 3 players. He observes that the player A can hit a target 4 times in 5 shots, player B can hit 3 times in 4 shots and the player C can hit 2 times in 3 shots. From this situation answer the following:P(A) = Probability of A hitting the target = 𝟒/𝟓 P(B) = Probability of B hitting the target = 𝟑/𝟒 P(C) = Probability of C hitting the target = 𝟐/𝟑 Question 1 Let the target is hit by A, B and C. Then, the probability that A, B and, C all will hit, is (a) 4/5 (b) 3/5 (c) 2/5 (d) 1/5P(all hit) = Probability A will hit × Probability B will hit × Probability C will hit = 4/5 × 3/4 × 2/3 = 𝟐/𝟓 So, the correct answer is (c) Question 2 Referring to (i), what is the probability that B, C will hit and A will lose? (a) 1/10 (b) 3/10 (c) 7/10 (d) 4/10P(B and C will hit and A will lose) = Probability A will not hit × Probability B will hit × Probability C will hit = (𝟏−𝟒/𝟓)"×" 𝟑/𝟒 × 𝟐/𝟑 = 1/5 × 3/4 × 2/3 = 𝟏/𝟏𝟎 So, the correct answer is (a) Question 3 With reference to the events mentioned in (i), what is the probability that ‘any two of A, B and C will hit? (a) 1/30 (b) 11/30 (c) 17/30 (d) 13/30 P(any two will hit) = P(A will not hit) × P(B will hit) × P(C will hit) + P(A will hit) × P(B will not hit) × P(C will hit) + P(A will hit) × P(B will hit) × P(C will not hit) = (1−4/5)"×" 3/4 × 2/3 + 4/5 "×" (1−3/4)× 2/3 +4/5 "×" 3/4 × (1−2/3) = 1/5 "×" 3/4 × 2/3 + 4/5 "×" 1/4 × 2/3 +4/5 "×" 3/4 × 1/3 = 1/10+2/15+1/5 = 𝟏𝟑/𝟑𝟎 So, the correct answer is (d) Question 4 What is the probability that ‘none of them will hit the target’? (a) 1/30 (b) 1/60 (c) 1/15 (d) 2/15P(none will hit) = Probability A will not hit × Probability B will not hit × Probability C will not hit = (𝟏−𝟒/𝟓) × (𝟏−𝟑/𝟒)×(𝟏−𝟐/𝟑) = 1/5×1/4×1/3 = 𝟏/𝟔𝟎 So, the correct answer is (b) Question 5 What is the probability that at least one of A, B or C will hit the target? (a) 59/60 (b) 2/5 (c) 3/5 (d) 1/60P( at least one will hit) = P(exactly one will hit) + P(exactly two will hit) + P(all will hit) P(exactly one will hit) P(exactly one will hit) = P(A will hit)×P(B will not hit) × P(C will not hit) + P (A will not hit) × P (B will hit) × P (C will not hit) + P (A will not hit)× P (B will not hit) × P (C will hit) = 4/5×(1−3/4)×(1−2/3) +(1−4/5)×3/4×(1−2/3) +(1−4/5)×(1−3/4)×2/3= 4/5 "×" 1/4 × 1/3 + 1/5 "×" 3/4× 1/3 +1/5 "×" 1/4 × 2/3 = 1/15+1/20+1/30 = 𝟗/𝟔𝟎P(exactly two will hit) This is calculated in Question 3 P(exactly two will hit) = 𝟏𝟑/𝟑𝟎 P(all will hit) This is calculated in Question 1 P(all will hit) = 𝟐/𝟓Now, P(at least one will hit) = P(exactly one will hit) + P(exactly two will hit) + P(all will hit) = 9/60+13/30+2/5 = 𝟓𝟗/𝟔𝟎 So, the correct answer is (a)

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• ICSE Class 8
• ICSE Class 8 Selina Solutions
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• ICSE Class 8 Maths Selina Solutions Chapter 23 Probability

Selina Solutions Concise Maths Class 8 Chapter 23: Probability

Selina Solutions Concise Maths Class 8 Chapter 23 Probability is one of the important chapters as it would be continued in higher levels of education. For this purpose, it is necessary for the students to understand each and every concept covered in this chapter clearly. Students will be able to cross check their answers while solving the textbook questions and understand the topics which they are weak at. Here, the students can download the ICSE Selina Solutions Class 8 Maths Chapter 23 Probability PDF, from the link which is given below.

Probability is a branch of Mathematics which is concerned with how likely an event is to occur or if that proposition is true. Students who aspire to perform well in the Class 8 exams are advised to solve the problems on a daily basis. It will also help them to clear their queries on time without any confusion.

Download ICSE Class 8 Maths Selina Solutions Chapter 23:- Download Here

Access Selina Solutions Concise Maths Class 8 Chapter 23: Probability

A die is thrown, find the probability of getting:

 (i) A prime number 

 A die has six numbers: 1, 2, 3, 4, 5, 6

No. of possible outcomes =6

We know that

Number of favorable outcomes = a prime number = 1, 3, 5 which are 3 in numbers (Formula)

 (ii) A number greater than 4 

No. of favorable outcome = Greater than four i.e. two number 5 and 6

(iii) A number not greater than 4. 

Number of favorable outcome = not greater than 4 or numbers will be 1,2,3,4 which are 4 in numbers

Question 2. 

A coin is tossed. What is the probability of getting

(i) A tail?

 On tossing a coin once,

No. of possible outcome =2

(i) Favorable outcome getting a tail =1

No. of favorable outcome =2

(ii) a head? 

Favorable outcome getting a head  =1

Question 3. 

 A coin is tossed twice. Find the probability of getting: 

 (i) Exactly one head

Exactly one head

Possible number of favorable outcomes =2  (i.e. TH and HT)

Total number of possible outcomes =4

(ii) Exactly one tail 

Exactly one tail

Possible number of favorable outcomes =2 (i.e. TH and HT)

(iii) Two tails

Possible number of favorable outcomes =1  (i.e. TT)

(iv) Two heads

Possible number of favorable outcomes =1 (i.e. HH)

Total number of possible outcomes = 4

Question 4. 

A letter is chosen from the word ‘PENClL’ what is the probability that the letter chosen is a consonant?

Total no. of letters in the word ‘PENCIL’ =6

Total Number of Consonant = ‘PNCL’ i.e, 4

Question 5. 

A bag contains a black ball, a red ball and a green ball, all the balls are identical in shape and size. A ball is drawn from the bag without looking into it. What is the probability that the ball drawn is:

(i) a red ball

Total number of possible outcomes =3

P (E) = 1/3

 (ii) Not a red ball 

No. of favorable outcomes

P (E) = 2/3

 (iii) A white ball. 

No. of favorable outcomes =0

P (E) = 0/3 = 0

Question 6. 

In a single throw of a die, find the probability of getting a number

(i) Greater than 2

 A die has six numbers =1, 2, 3,4,5,6

Question 7.

A bag contains 3 white, 5 black and 2 red balls, all of the same shape and size.

A ball is drawn from the bag without looking into it, find the probability that the ball drawn is:

(i) a black ball.

(ii) a red ball.

(iii) a white ball.

(iv) not a red ball.

(v) not a black ball.

In a bag, 3 balls are white

2 balls are red

5 balls are black

Total number of balls =3+2+5=10

(i)   Number   of   possible   outcomes   of   one   black   ball   =10   and   number   of   favorable   outcome   of   one   black   ball   =5

In a single throw of a die, find the probability that the number:

(i) Will be an even number.

(ii) will be an odd number.

(iii) will not be an even number.

A die has six numbers:  1, 2, 3, 4, 5, 6

Number of possible outcome =6

(i) Number of favorable outcome = an even number i.e.  2, 4, 6 which are 3 in numbers

Question 9. 

In a single throw of a die, find the probability of getting:

(ii) a number greater than 8

(iii) a number less than 8

On a die the numbers are 1, 2, 3, 4, 5, 6  i.e, six.

(i) Number of favorable outcome =0

(∵8 is not possible)

Question 10. 

Which of the following cannot be the probability of an event?

The probability of an event cannot be

(ii) 3.8 i.e., the probability of an even cannot exceed 1.

(iv) i.e., -0.8

(vi) −2/5, because probability of an even can never be less than 1.

Question 11.

A bag contains six identical black balls. A child withdraws one ball from the bag without looking into it. What is the probability that he takes out:

(i) a white ball,

(ii) a black ball

There are 6 black balls in a bag

Number of possible outcome =6

(i) A white ball

As there is no white ball in the bag

Probability is zero (0) = or P(E)=0

Number of favorable outcome =1

Question 12.

Three identical coins are tossed together. What is the probability of obtaining?

(i) All heads?

(ii) Exactly two heads?

(iii) Exactly one head?

(iv) No head?

Total outcomes =8

i.e. (H,H,H),(H,H,T),(H,T,H),(T,T,T),(T,H,H),(T,T,H),(H,T,T),(T,H,T)

(i) Favorable outcome= i.e. (H,H,H)

Question 13.

A book contains 92 pages. A page is chosen at random. What is the probability that the sum of the digits in the page number is 9?

Number of pages of the book =92 which are from 1 to 92

Number of possible outcomes =92

Number of pages whose sum of its page is 9=10

i.e. 9,18,27,36,45,54,63,72,81,90

Question 14.

Two coins are tossed together. What is the probability of getting:

(i) at least one head

(ii) both heads or both tails.

A coins has two faces Head and Tail or H.T

Two coins are tossed

Number of coins =2×2=4 which are HH, HT, TH, TT

(i) At least one head, then Number of outcomes =3

Question 15.

From 10 identical cards, numbered 1, 2, 3,…, 10, one card is drawn at random. Find the probability that the number on the card drawn is a multiple of:

(iii) 2 and 3

(iv) 2 or 3

Total outcomes =10

i.e. 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

(i) Favorable outcomes =5 i.e. 2, 4, 6, 8, 10

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CBSE 10th Standard Maths Subject Probability Case Study Questions 2021

By QB365 on 22 May, 2021

QB365 Provides the updated CASE Study Questions for Class 10 Maths, and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get  more marks in Exams

QB365 - Question Bank Software

10th Standard CBSE

Final Semester - June 2015

Case Study Questions

(ii) a monkey

(iii) a teddy bear

(iv) not a monkey 

(v) not a pokemon 

(ii) If the probability of distributing dark chocolates is 4/9, then the number of dark chocolates Rohit has, is

(iii) The probability of distributing white chocolates is

(iv) The probability of distributing both milk and white chocolates is

(v) The probability of distributing all the chocolates is

In a party, some children decided to play musical chair game. In the game the person playing the music has been advised to stop the music at any time in the interval of 3 mins after he start the music in each turn. On the basis of the given information, answer the following questions. (i) What is the probability that the music will stop within first 30 sees after starting?

(ii) The probability that the music will stop within 45 sees after starting is

(iii) The probability that the music will stop after 2 mins after starting is

(iv) The probability that the music will not stop within first 60 sees after starting is

(v) The probability that the music will stop within first 82 sees after starting is

(ii) The probability of getting exactly 1 head is

(iii) The probability of getting exactly 3 tails is 

(iv) The probability of getting atmost 3 heads is 

(v) The probability of getting atleast two heads is

(ii) not of yellow colour

(iii) of green colour

(iv) of yellow colour 

(v) not of blue colour 

*****************************************

Cbse 10th standard maths subject probability case study questions 2021 answer keys.

Total number of puppets in claw crane = 58 + 42 + 36 + 64 = 200 (i) (b): P(picking a tiger) =  \(\begin{equation} \frac{36}{200}=\frac{9}{50} \end{equation}\) (ii) (a): P(picking a monkey) =  \(\begin{equation} \frac{64}{200}=\frac{8}{25} \end{equation}\) (iii) (c) : P(picking a teddy bear) =  \(\begin{equation} \frac{58}{200}=\frac{29}{100} \end{equation}\) (iv) (d) : P(not picking a monkey) = 1 - P(picking a monkey) \(\begin{equation} =1-\frac{8}{25}=\frac{17}{25} \end{equation}\) (v) (d): P(picking a pokemon) =  \(\begin{equation} \frac{42}{200}=\frac{21}{100} \end{equation}\) P(not picking a pokemon) = 1 - P(picking a pokemon) \(\begin{equation} =1-\frac{21}{100}=\frac{79}{100} \end{equation}\)

Since, every student get one chocolate. So, number of chocolates Rohit has is equal to the number of students in the class. (i) (a): Let number of milk chocolates Rohit has = x Probability of distributing milk chocolates =  \(\begin{equation} \frac{1}{3} \end{equation}\) \(\begin{equation} \Rightarrow \frac{x}{54}=\frac{1}{3} \Rightarrow x=\frac{54}{3}=18 \end{equation}\) (ii) (c): Let number of dark chocolates Rohit has = y Probability of distributing dark chocolates =  \(\begin{equation} \frac{4}{9} \end{equation}\) \(\begin{equation} \Rightarrow \frac{y}{54}=\frac{4}{9} \Rightarrow y=\frac{4 \times 54}{9}=24 \end{equation}\) (iii) (d) : Number of white chocolates Rohit has = 54 -(18 + 24) = 12 Required probability =  \(\begin{equation} \frac{12}{54}=\frac{2}{9} \end{equation}\) (iv) (b) : Total number of milk and white chocolates = 18 + 12 = 30 Required probability =  \(\begin{equation} \frac{30}{54}=\frac{5}{9} \end{equation}\) (v) (b): Since all students gets one chocolate. So, total number of chocolates distributed = 54 \(\begin{equation} \text { Required probability }=\frac{54}{54}=1 \end{equation}\)

Total time = 3 mins = 3 x 60 sees = 180 secs (i) (a): Required probability =  \(\begin{equation} \frac{30}{180}=\frac{1}{6} \end{equation}\) (ii) (a): Required probability =  \(\begin{equation} \frac{45}{180}=\frac{1}{4} \end{equation}\) (iii) (d) : P(music will stop within 2 mins) =  \(\begin{equation} \frac{120}{180}=\frac{2}{3} \end{equation}\) P(music will stop after 2 mins) =  \(\begin{equation} 1-\frac{2}{3}=\frac{1}{3} \end{equation}\) (iv) (b) : Required probability = 1 - P(music will stop within first 60 secs) \(\begin{equation} =1-\frac{60}{180}=1-\frac{1}{3}=\frac{2}{3} \end{equation}\) (v) (b): Required probability =  \(\begin{equation} \frac{82}{180}=\frac{41}{90} \end{equation}\)

Sample space (5) = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} \(\Rightarrow\) n(5) = 8 (i) (c): Let A be the event of getting atmost one tail.  A = {HHH, HHT, HTH, THH} \(\Rightarrow\) n(A) = 4 Required probability =  \(\begin{equation} \frac{4}{8}=\frac{1}{2} \end{equation}\) (ii) (d ): Let B be the event of getting exactly 1 head. B = {HTT, THT, TTH} \(\Rightarrow\)  n(B) = 3 Required probability =  \(\begin{equation} \frac{3}{8} \end{equation}\) (iii) (d) : Let C be the event of getting exactly 3 tails. C = {TTT}  \(\Rightarrow\)  n( C) = 1 Required probability =  \(\begin{equation} \frac{1}{8} \end{equation}\) \(\begin{equation} \frac{1}{8} \end{equation}\) \(\begin{equation} \frac{1}{8} \end{equation}\) \(\begin{equation} \frac{1}{8} \end{equation}\) (iv) (b) : Let D be the event of getting atmost 3 heads. D = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} \(\Rightarrow\) n(D) = 8 Required probability =  \(\begin{equation} \frac{8}{8}=1 \end{equation}\) (v) (c): Let E be the event of getting atleast two heads. E = {HHT, HTH, THH, HHH} \(\Rightarrow\) n(E) = 4 Required probability =  \(\begin{equation} \frac{n(E)}{n(S)}=\frac{4}{8}=\frac{1}{2} \end{equation}\)

Total number of blocks in the kit = 120 Number of red blocks = 40 Number of blue blocks = 25 Number of green blocks = 30 Number of yellow blocks = 120 - (40 + 25 + 30) = 120 - 95 = 25 (i) (d): P(block is red)  \(\begin{equation} =\frac{40}{120}=\frac{1}{3} \end{equation}\) (ii) (c): P(block is not yellow) = 1 - P(block is yellow) \(\begin{equation} =1-\frac{25}{120}=1-\frac{5}{24}=\frac{19}{24} \end{equation}\) (iii) (c) : P(block is green) =  \(\begin{equation} \frac{30}{120}=\frac{1}{4} \end{equation}\) (iv) (b) : P(block is yellow) =  \(\begin{equation} \frac{5}{24} \end{equation}\) (v) (b): P(block is not blue) = 1 - P(block is blue) \(\begin{equation} =1-\frac{25}{120}=1-\frac{5}{24}=\frac{19}{24} \end{equation}\)

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CBSE Class 10 Maths Case Study Questions for Chapter 15 - Probability (Published by CBSE)

Check case study questions for cbse class 10 maths chapter 15 - probability. these questions are published by the cbse board and are important for the class 10 maths exam 2021-22..

CBSE Class 10 Maths Case study questions for Chapter 15 - Probability are published by the CBSE board. These questions are prepared in the form of Multiple Choice Type Questions. Students must solve these questions to understand in what ways the case study questions can be asked in the exam. Answers to all the questions are also provided along with them.

Case Study Questions for Class 10 Maths Chapter 15 - Probability

CASE STUDY 1:

On a weekend Rani was playing cards with her family . The deck has 52 cards. If her brother drew one card.

1. Find the probability of getting a king of red colour.

Answer: a) 1/26

2. Find the probability of getting a face card.

Answer: d) 3/13

3. Find the probability of getting a jack of hearts.

Answer: b) 1/52

4. Find the probability of getting a red face card.

Answer: a) 3/13

5. Find the probability of getting a spade.

Answer: d) 1/4

CASE STUDY 2:

Rahul and Ravi planned to play Business ( board game) in which they were supposed to use two dice.

1. Ravi got first chance to roll the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 8?

Answer: b) 5/36

2. Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 13?

Answer: d) 0

3. Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is less than or equal to 12 ?

Answer: a) 1

4. Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is equal to 7?

Answer: c) 1/6

5. Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is greater than 8?

Answer: d) 5/18

Also Check:

CBSE Class 10 Maths Case Study Questions - All Chapters

Tips to Solve Case Study Based Questions Accurately

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